By what factor does the pressure of the gas increase if the gas is compressed to half its original volume? Heat capacity, in general, depends on the process of the system that goes through when the heat is supplied. The net heat absorbed by the system when the gas changes its state from state P to state Q is: Since heat absorbed,ΔQ=ΔU+ΔW\Delta Q=\Delta U+\Delta WΔQ=ΔU+ΔW, Therefore, ΔW=ΔQ−ΔU\Delta W=\Delta Q-\Delta UΔW=ΔQ−ΔU These ncert book chapter wise questions and answers are very helpful for CBSE exam. Easy notes that contain numerical problems of the chapter. (a) Two bodies at different temperatures T1 and T2, if brought in thermal contact do not necessarily settle to the mean temperature (T1 + T2)/2 ? Answer: Question 12. thermodynamics and express it mathematically; • calculate energy changes as ... CBSE Class 11 Physics. NCERT Solutions for Class 11 Physics. NCERT Solutions for Class 11-science Physics CBSE, 12 Thermodynamics. ), Universal gas Constant, R = 8.3 J mol – 1 K – 1, Mass of Nitrogen, m = 1.8 × 10 – 2 kg = 18 g, Now, the number of moles, n = mass of N2Molicular mass of N2=mM=1828\frac{mass\;of\;N_{2}}{Molicular\;mass\;of\;N_{2}}=\frac{m}{M}=\frac{18 }{28}MolicularmassofN2massofN2=Mm=2818, Now, for Nitrogen Molar specific heat at constant pressure CP = 72×R=72×8.3\frac{7}{2}\times R=\frac{7}{2}\times 8.327×R=27×8.3. Before we discussed the Pradeep Book Solution for Class 11. Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter. We are concerned only with work done by a system on its surroundings or […] The intermediate states do not satisfy the gas equation and since they are in non – equilibrium states, they do not lie on the Pressure-Volume – Temperature surface of the system. Thermodynamics Nootan Solutions ISC Class-11 Physics Nageen Prakashan Ch-19 Numericals of latest edition. ... CBSE Class 11-science Sample Papers and Solutions. Students must study this chapter in-depth to excel in the exam. 0. Therefore, the initial temperature, T1 = 27 °C, And, the final temperature, T2 = 77 °C, Hence, the rise in temperature, Δ\DeltaΔT = T2 – T1, And, specific heat of water, c = 4.2 J g – 1 °C – 1, Now, Mass of flowing water, m = 4.0 litres/min, i.e. Therefore, a liquid with a high specific heat value is the best coolant to be used in a nuclear or chemical plant. If the system performs work at a rate of 75 joules per second. (c) What is the change in the temperature of the gas? (b) The coolant in a chemical or a nuclear plant (i.e., the liquid used to prevent the different parts of a plant from getting too hot) should have high specific heat. State second law of thermodynamics. Answer: (a) Since the final temperature and initial temperature remain the same, The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. B is completely evacuated. This is possible because of the infinitesimal difference in temperature between the system and the reservoir. Question 1. Also after the chapter you can get links to Class 11 Physics Notes, NCERT Solutions, Important Question, Practice Papers etc. Answer: (a) In thermal contact, heat flows from the body at higher temperature to the body at lower temperature till temperatures become equal. Thermodynamics Class 11th. As a result, the gas can not return to an equilibrium state which lie on the P-V-T surface. The NCERT Class 11th Physics textbooks are well known for it’s updated and thoroughly revised syllabus. 100 Qs. Scroll down for Thermodynamics from NCERT Book Class 11 Physics Book & important study material. Visit official Website CISCE for detail information about ISC Board Class-11 Physics. Let us check the CBSE Class 11 Physics Syllabus. branch of physics which is concerned with the relationship between other forms of energy and heat Q.4: A cylinder with a movable piston contains 3 moles of hydrogen at standard temperature and pressure. These ncert book chapter wise questions and answers are very helpful for CBSE exam. ΔU=ΔQ−ΔW\Delta U=\Delta Q-\Delta WΔU=ΔQ−ΔW= 0 – ( -23.2 ). How much heat is wasted per minute? (ii).The coolant used in a chemical or nuclear plant should always have a high specific heat. In this chapter, you will study about laws of thermodynamics, thermal equilibrium, heat capacity, and various other topics. What is the efficiency of the engine? Define temperature on the basis of zeroth law of thermodynamics. Thermodynamics class 11 Notes Physics. If the geyser operates on a gas burner, ... From the first law of thermodynamics, we have: NCERT Class 11 Physics Notes | Textbook | Solution | | Exemplar | Exemplar Solution | Quick Notes | Short Notes | Model Paper and Many More Reading Material are Added for CBSE Students. These important questions from thermodynamics class 11 physics will play significant role in clearing concepts of Physics. The above case is the clear case of free expansion and free expansion is rapid and it cannot be controlled. Thermodynamics Physics First law Second Law Zero Law Cp Cv Work Heat Thermal Equilibrium Carnot's Heat Engine Isothermal Adiabatic 6. Question 12. CBSE Class 12 Chemistry , CBSE Class 12 Physics. (d) The climate of a harbour town is more temperate than that of a town in a desert at the same latitude. 2 What amount of heat must be supplied to 2.0 x 10-2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? 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